Question

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Answer 1

Hey beautiful

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To Prove ABC + ACD = 2A C

AL in the angle bisector of A, so let BAL = LAC = x

Then, using exterior angle property

∠ALC = x + alpha ..(1)

Similarly

∠ACD= 2x + ..(2)

Hence from (1) and (2), we get

ABC + ACD = 2ALC

(i.e.)

( alpha ) + (2x + alpha ) = 2(x + alpha )

HENCE PROVED