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Given that SP || RQ :
So,
SP || RQ and QP is transversal,
So,
∠SPQ + ∠RQP = 180° { co-interior angles }
∠SPQ = 180° - 130°
∠SPQ = 50°
Similarly, SP || RQ and SR is transversal,
So,
∠QRS + ∠PSR = 180° { co-interior angles }
∠PSR = 180° - 90°
∠PSR = 90°
Hence, ∠P is 50° and ∠S is 90°
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Answer:
angle r + angle s = 180 (as sp is parallel to each other)
90+ angle s = 180
angle S = 180-90
angle S = 90
q+r+s+p= 360 ( as sum of all angles of quadrilateral is 360)
130 + 90+90+angle p = 360
310 + angle p = 360
angle p = 360 - 310
angle p = 50
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