Question

plzz answer fastt guys​

Answer 1

Answer:

which one ? there are two 27 ,28

Step-by-step explanation:

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Answer 2

Answer 27) :-

given ,

• Radius of hemispherical vessel = 14cm.

So,

→ Volume of sand = (2/3) * π * (radius)³ = (2/3) * (22/7) * (14)³ = (44/3) * (2 * 196) = (44 * 392)/3 cm³

Now, this sand is poured on a level ground of cone shape with height 7 cm. Let us assume that radius of cone is r cm.

then,

→ Volume of cone = volume of sand .

→ (1/3) * π * (r)² * h = (44 * 392)/3

→ (1/3) * (22/7) * (r²) * 7 = (44 * 392)/3

→ 22r² = (44 * 392)

dividing both sides by 7,

→ (22/7)r² = (44 * 392)/7

→ Base Area = 56 * 44 = 2464 cm² (Ans.)

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Answer 28) :-

→ 4tanA = 3

→ tanA = 3/4 = Perpendicular / Base

So,

• Perpendicular = 3 .
• Base = 4 .

then,

→ Hypotenuse = √[(P² + B²] = √[3² + 4²] = √[9 + 16] = √25 = 5 .

So,

• sinA = P/H = 3/5 .
• cosA = B/H = 4/5 .

therefore,

→ (4sinA - cosA + 1) / (4sinA + cosA - 1)

→ {4*(3/5) - (4/5) + 1} / {4*(3/5) + (4/5) - 1}

→ {(12/5) - (4/5) + 1} / {(12/5) + (4/5) - 1}

→ {(12 - 4 + 5)/5} / {(12 + 4 - 5)/5}

→ (13/5) / (11/5)

→ (13/5) * (5/11)

→ (13/11) (Ans.)

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