Question

plzz answer friends plzzz urgent

Answer 1

Let,
angle AOC = x
angle AFC = y
and angle AEC = z

Now from my above image,

As angle x is at centre,
So angle ABC will be x/2.......(1)

(According to a theorem, angle AOC = 2 times of angle ABC)

Also, angle ADC = x/2.........(2)

Now, angle EBC & angle EDA will be π - (x/2)............(3)

And, angle AFC = angle DFB.......(4)
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Now, EBFD is a quadrilateral,

So summation of all angles will be 2π (360°)

So,

2π = angleAEC + angleEDF + angleEBC + angleDFB

(Using (1), (2), (3) & (4))

2π = z + π - (x/2) + π - (x/2) + y

2π = z + 2π - x + y

x = z + y

Thus,

angle AOC = angle AEC + angle AFC

"Thanks"