Question

plzz answer i will mark brainliest

Answer 1

here is your answer

given: parallelogram AC=BD
To proove: ABCD is a rectangle 
TP; one of its interior angle is 90 degree

consider triangle ABC and DCB
AC=BD (given)
AB=DC (opposite sides of parallelogram)
BC=BC (common)
triangle ABC congruent - triangle DCB (by SSS rule)
angle ABC= angle DCB (by CPCT)

2nd proof (one of its interior angle is 90 degree)
BC is the transversal 
angle ABC + angle DCB = 180 degree (co-interior angle)
angle ABC + angle ABC= 180 degree
2 angle ABC= 180 degree
angle ABC= 180/2
= 90 degree
therefore, ABCD is a rectangle

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