Question

plzz answer it fast.......​

Answer 1

Step-by-step explanation:

y^2 + 4y +8 is the answer

p(y)= y^2 - ( alpha + beta)y + alpha ×beta

= y^2 -( -4 )y +8

= y^2 +4y +8

it will have infinite solutions because an equation with two variables will obviously have infinite solutions

Answer 2

Answer:

THE QUADRATIC EQUATION WITH THE GIVEN CONDITION WILL BE:

${y}^{2} + 4y + 8$