Question

plzz.... answer it... guyss it's important

Answer 1

ab aage ka aap solve ker lo

Answer 2

Hey !!!

Solution :-

given

$\sqrt{3 \sqrt{3 \sqrt{3 \sqrt{3 \sqrt{3...... \infty } } } } } = x$ -------1)
(given )

Squaring on both side

we get

x² =
$( \sqrt{3)} {}^{2} + \sqrt{3 \sqrt{3 \sqrt{3..... \infty = x ^{2}$

=> 3 - x = x²

=> x² + x - 3 = 0

Now by using quadratic formula

x² + x - 3

D = b² -4ac

D= 1² - 4×1×(-3)

D = 1 + 12

D = 13

$\alpha and \beta = - b {}^{2} + - \sqrt{d} \div 2a$

=> (-1)² +- √13/2×1

Alpha = 1 - √13/2

=> 1 - 3.60555128 /2

=> -2.60 /2 =- 1.30 Approax

and bita = 1+√13/2

=> 1 + 3.60555128/2

=> 4.60/2 = 2.30 Approax value ...

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Hope it helps you !!!

.#Rajukumar111