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∠DAB + ∠EBA = 180°
⇒ 2∠CAB + 2∠CBA = 180°(Using (1) and (2))
⇒ ∠CAB + ∠CBA = 90°
In ∆ABC,
∠CAB + ∠CBA + ∠ABC = 180° (Angle sum property)
⇒ 90° + ∠ABC = 180°
⇒ ∠ABC = 180° - 90° = 90°
Thus, the bisectors of two adjacent supplementary angles include a right angle.
I guess....
⇒ 2∠CAB + 2∠CBA = 180°(Using (1) and (2))
⇒ ∠CAB + ∠CBA = 90°
In ∆ABC,
∠CAB + ∠CBA + ∠ABC = 180° (Angle sum property)
⇒ 90° + ∠ABC = 180°
⇒ ∠ABC = 180° - 90° = 90°
Thus, the bisectors of two adjacent supplementary angles include a right angle.
I guess....
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