Question

plzz answer me......
i give u thnks if u give me right answer​

Answer 1

Answer:

first prove that the perpendicular at the point of contact is radius and so it passes through center

Answer 2

Given a circle with center O and AB the tangent intersecting circle at point P
and prove that OP⊥AB
We know that tangent of the circle is perpendicular to radius at points of contact Hence
OP⊥AB
So, ∠OPB=90
o
..........(i)
Now lets assume some point X
Such that XP⊥AN
Hence ∠XPB=90
o
.........(ii)
From eq (i) & (ii)
∠OPB=∠XPB=90
o

Which is possible only if line XP passes though O
Hence perpendicular to tangent passes though centre
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