plzz answer me this question it's urgent
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Step-by-step explanation:Given ax + by = 1 , bx+ay = [(a+b)2 ]/ [a2 +b2] - 1
ax + by = 1 ----------------(1) , bx+ay = 2ab/ [a2 +b2] --------------(2)
adding (1) and (2)
(a+b)x + (a+b)y = 1 + 2ab/ [a2 +b2]
(a+b)(x + y) = (a+b)2 / [a2 +b2]
x + y = (a+b) / [a2 +b2] ---------------(3)
substracting (2) from (1)
(a-b)x - (a-b)y = 1 - 2ab/ [a2 +b2]
(a-b)(x - y) = (a-b)2 / [a2 +b2]
x - y = (a-b) / [a2 +b2] ---------------(4)
adding (3) and (4)
2x = 2a / (a2 +b2)
x = a / (a2 +b2) .
substracting (4) from (3)
2y = 2b / (a2 +b2 )
y = b / (a2 +b2 )Therefore the solution x = a / (a2 +b2) y = b / (a2 +b2 )
hope it would be helpful..................
nanduss:
thank uuu
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