Plzz answer my question
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basheeramaryam:
okay...
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Answered by
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According to me it's 4.8.
Hope it helps you. Mark this answer as brainlist plz.
By that:
pH= pKa + log ([HCOO]-/[HCOOH])
pH=3.8 +log (0.50M/0.27M)
{M and M got cut}
pH=3.8 + log (0.50/0.27)
pH=3.8 +0.268
pH= 4.068
pH= 407 or 4.8 (approx)
Hope it helps you. Mark this answer as brainlist plz.
By that:
pH= pKa + log ([HCOO]-/[HCOOH])
pH=3.8 +log (0.50M/0.27M)
{M and M got cut}
pH=3.8 + log (0.50/0.27)
pH=3.8 +0.268
pH= 4.068
pH= 407 or 4.8 (approx)
But how
Thank you
wlcm...
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