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your answer is 24 cm apart from 10 cm radius
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Dist. of half chord=24/2=12cm(since line drawn perpendicular to chords for the centre bisect the chord)
A right angled triangle is made;
By using Pythagoras Theorem:
(13)^2=(12)^2+x^2 (let dist between chord and centre=x)
169=144+x^2
x^2=169-144
x^2=25
x= √25=5cm
Therefore, the dist. between the chord and centre is 5cm.
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