plzz answer no 20 in the following image through logarithm
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hrik211:
plzz answer it wth full explanation
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hope this wil help you...solved by my brother.
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LHS = ( log√27 + log8 + log√1000 )/log120
= { log( 3√3) + log8 + log(10√10) }/log120
[ use , logm + logn = logmn ]
= { log( 3√3 × 8 × 10√10) }/log120
= { log( 240√30 )}/log120
= { log( 120 √120)}/ log120
[ use logmn = logm + logn ]
= { log120 + log√120}/log120
= log120/log120 + log(120)½/log120
[ use, log(x)ⁿ = nlogx ]
= 1 + 1/2 { log120/log120}
= 1 + 1/2 = 3/2 = RHS
= { log( 3√3) + log8 + log(10√10) }/log120
[ use , logm + logn = logmn ]
= { log( 3√3 × 8 × 10√10) }/log120
= { log( 240√30 )}/log120
= { log( 120 √120)}/ log120
[ use logmn = logm + logn ]
= { log120 + log√120}/log120
= log120/log120 + log(120)½/log120
[ use, log(x)ⁿ = nlogx ]
= 1 + 1/2 { log120/log120}
= 1 + 1/2 = 3/2 = RHS
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