Plzz answer.
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Step-by-step explanation:
Since AB||CD, BC is the transversal.
∠ABC = ∠DCB (Alternate angles)
=> 70° = ∠3.
We know that sum of all angles at ∠C should be 180°
=> 45° + ∠3 + ∠2 = 180°
=> 45° + 70° + ∠2 = 180° (∵ ∠3 = 70°)
=>∠2 = 180 - 115 = 65°.
Now we now that sum of all angles in a triangle is always equal to 180°.
=> ∠1 + ∠2 + 70° = 180°
=> ∠1 + 65° + 70° = 180° (∵ ∠2 = 65°)
=> ∠1 = 180 - 135 = 45°.
Thus ∠1 = 45°, ∠2 = 65° and ∠3 = 70°
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