Question

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Answer 1

Answer:

168cm ^2

Step-by-step explanation:

we know that the area or rectangle minus area of the white portion = area of shaded portion

side AD= 14

:. AE= 10

lets find the area of TRI EAF

1/2 *b*h

1/2 *10*12

60 cm ^2

lets find the area of tri. FBC

1/2*b*h

1/2*10*14

70 cm ^2

now area of rectangle = l*b = 14*22=308cm ^2

308- (70+60) = area of shaded portion

308-130 = 168 cm ^2

Area of shaded portion = 168cm^2

Answer 2

178 cm sq.

STEP BY STEP EXPLANATION

In the rectangle ABCD

At the first we will find the areas of two triangles FBC and FAE

Area of ∆FBC

Area of a ∆=

$\frac{1}{2} \times b \times h$

$\frac{1}{2} \times 10 \times 14$

$70cm ^{2}$

Area of ∆ FAE=

$\frac{1}{2} \times b \times h$

$\frac{1}{2} \times 12 \times 10$

$60cm^{2}$

Total areas of both triangles

$60cm^{2} + 70cm ^{2}$

$130cm^{2}$

Area of the rectangle ABCD

Area of rectangle= L×B

= 22×14

=

$308cm^{2}$

Area of the shaded portion

$308cm^{2} - 130cm^{2}$

$178cm^{2}$