Question

plzz answer que 11
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Answer 1

Answer:

In ∆PQR

BC parallel to RQ

acc to mid point therom,BC=1/2RQ....... (1)

similarly, AC=1/2PQ........ (2)

AB=1/2PR......... (3)

Add eq (1), (2), (3)

AB+BC+CA= 1/2PR+1/2RQ+1/2PQ

AB+BC+CA= 1/2(PR+RQ+PQ)

2(AB+BC+CA)= PR+RQ+PQ

hence proved