plzz answer ques no 5
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first son age 10 years ago= X+2
2nd son age 10 years ago = X
father age 10 years ago = 1/3 of sum of sons age SO
(X+X+2)/3
2X+2÷3
present age of first son =X+2+10
present age of second son=X+10
some of their present age is 14 years less than the fathers age So
(2X+12)/3=2X+22+14
14 because they are 14 years less than the fathers age
simplification of above equation gives X=22.5 years
1st son age = 24.5
2nd son age 10 years ago = X
father age 10 years ago = 1/3 of sum of sons age SO
(X+X+2)/3
2X+2÷3
present age of first son =X+2+10
present age of second son=X+10
some of their present age is 14 years less than the fathers age So
(2X+12)/3=2X+22+14
14 because they are 14 years less than the fathers age
simplification of above equation gives X=22.5 years
1st son age = 24.5
ssv9989:
i think it is correct is there any mistake plz reply me
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I think it is right answer If you like please mark as brainliest
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