plzz answer question
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hey dude
There are only 2 probabilities here one is of odd and another is of even ....
let p(even) = 7/10 so p(odd) =X
p(even) + p(odd) = 1
7/10+X = 1
x = 1-7/10
x= 3/10
p(odd) = 3/10
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if u want to be objective
by logic u can see that out of 10 , 7 are even so 3 out of 10 will be odd .....
hope it helps .....ask if any doubt
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