Question

Plzz answer Question no. 5 As given in image

Answer 1

Answer:

If p and q are the roots of the equation x2 +bx+c then:

p+q=(-b)/a = -(-(k+6))/1

p*q=c/a = 2(2k-1)/1

According to the information: p+q=1/2(p*q)

k+6=(1/2) *(2*( 2k-1))

solve it and see that it comes to.....

k+5=2k-1 [subtract both sides by k]

5=k-1

k=5

SOLVED,

HOPE YOU UNDERSTOOD,GOOD LUCK!!!

Answer 2

HOPE ITS HELPFUL.....:-)