Question

plzz answer the marked ones with red colour.​

Answer 1

Answer:

y=(x-1)(x-2)/√x. [Assuming function which is logarithmic differentiation to compute this derivative]

ln y=ln[(x-1)(x-2)/√x]

ln y=ln(x-1)+ln(x-2) -ln√x

ln y=ln(x-1)+ln(x-2)-ln(x)^1/2

ln y=ln(x-1)+ln(x-2)-1/2ln(x)

1/y(dy/dx)= 1/x-1 +1/(x-2) -1/2x

dy/dx=y(1/x-1+1/x-2-1/2x)

dy/dx[(x-1)(x-2)/√x](1/x-1+1/x-2-1/2x)

Hope this helps..