Question

plzz answer the question

Answer 1

Answer:

Step-by-step explanation:

Length of the wire = 18cm

Let's name the wire as ACDB

AC = CD = 3cm from the firgure

⇒ DB = 18 - (3 + 3)

   DB = 12cm

(SORRY,I WASN'T ABLE TO ADD THE PICTURE, but try to visualize)

From point A, draw a ⊥r to line DB

Let's mark the point as 'X'

Now, ACDX is a square.

DX = 3cm (Sqaure ⇒ opp sides equal)

XB = DB - DX

     = 12 - 3

XB = 9cm

AX = 3cm.

Now, it's a right Δle.

Joining AB,

By using Pythagoras theorem,

AX² + XB² = AB²

3² + 9² = AB²

AB² = 9 + 81

AB² = 90

AB = √90

AB = 9.48cm.