plzz answer the question.
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Answer:
- a=6, d=4 & s8=160
Step-by-step explanation:
let a is the first term of the A.P &
d is the common difference
by the formula-
a+4d=22.....(1)
a+15d=66.....(2)
___________
-11d=-44
d=-44/-11
d=4
putting d=4 in equation 1
a+4d=22
a+4x4=22
therefore a=6
8th term of the A.P
sn=n/2[2a+(n-1)d]........(by formula)
s8=8/2[2x6+(8-1)4]
s8=4 [12+7x4]
s8=4x40
s8=160
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