Question

plzz answer the question ​

Answer 1

Here sin Ѳ=12/13=Height/Hypoteneuse

In a right-angeled triangle;

Hypoteneuse²=Base²+Height²

(13)²=Base²+(12)²

(13)²-(12)²=Base²

169-144=Base²

√25=Base

Therefore,Base=5

Now,

cosѲ=Base/Hypoteneuse=5/13

tanѲ=Height/Base=12/5

sin²Ѳ=(12/13)²=144/169. 2sinѲ=2×(12/13)

cos²Ѳ=(5/13)²=25/169

tan²Ѳ=(12/5)²=144/25

now put the values in to find the solution.

Hope this answer helps you please mark brainliest.

Answer 2

Answer:

-69.497

Step-by-step explanation:

we know that in right angled triangle we use phythagarous therorm from that we obtain three sides.

we know that

sin^2(a)-cos^2(a)=cos2(a)/

2sin(a)cos(a)=sin2(a)

sin2(a)/cos2(a)=tan2(a)

tan2(a)×{1+cos2(a)}\1-cos2(a)}=-69.487 radians