Math, asked by vanshaj78920, 1 year ago

plzz answer the question

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Answered by nikky28
2
Heya !!!

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 {kx}^{2}  + 2x + 1 \:  \: has \: real \: roots \:   \\  \\   here \: . \:   \\ a = k \\ b = 2 \\ c = 1\\  \\ discriminant \:   >  \: 0 \\  \\  =  >  {b}^{2}  - 4ac \:  >  \: 0 \\   \\  =  >  {(2)}^{2}  - 4(k)(1) \:  >  \: 0 \\  \\  =  > 4 - 4k \:  >  \: 0 \\  \\ =  >  4k \:  >  \: 4 \\  \\  =  > k \:  > 1 \:  \:  \: \:  \:  \:  \:  \:  \:  (an s)


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Hope it helps u !!!!

# Nikky
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