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please refer to the attachment .
→We know that direction of electric field is from high potential to low potential . So , the direction of electric field will be from B to A .
→ to reach A it must have some initial kinetic energy .
Option c ✔️✔️
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‼️ Êlõ ‼️
Here u go ....
we'll apply here energy conservation....
∆K = ∆V
K(f) - K(i) = -3eV -(-7eV)
K(f) - K(i) = 4eV
K(i) = 4eV + K(f)
This shows to reach A it must have KE more than or equal to 4eV at B.
☑️Option c
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