CBSE BOARD X, asked by singhchanda827, 10 months ago

plzz answer the question fast​

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Answers

Answered by suraj1910
0

Answer:

F = -30 cm

Height of object = 5 cm

V = 15 cm

\bf\huge\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

f

1

=

v

1

u

1

\bf\huge\frac{1}{-30}=\frac{1}{15} - \frac{1}{u}

−30

1

=

15

1

u

1

\bf\huge\frac{1}{u} = \frac{1}{15} + \frac{1}{30}

u

1

=

15

1

+

30

1

\frac{1}{u} = \frac{2+1}{30}

u

1

=

30

2+1

= \bf\huge\frac{3}{30}

30

3

=> U = 10 cm

Magnification = \bf\huge\frac{-V}{U}

U

−V

\bf\huge\frac{-15}{10} = \frac{hi}{5}

10

−15

=

5

hi

hi = -7.5

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