Question

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Answer 1

Answer:

1) 512

2) a) 20:18

=10:9

b) 2³=8

3²=9

hence 9>8

so, 3²>2³

3) a) a²-2ab+b²

b) with sides 5,4,10

lets consider any two sides say 4,10

and other side be x

by inequality Condition

difference of two sides<x<sum of two sides

10-4<x<10+4

6<x<14

so x should lie b/w 6 and 14 but 5 does not

so cant be formed

4)a) sum of sides lenght

( 4+3+5) cm=12cm

b) 180°-135°=45°

45°is yhe supplyment of 135°

5) -9p²q³+(-5p³q²) +6p³q²+10p²q³

p²q³+p³q²

10) 81/100

13)c+x=180 →c=180-x...... 1

a+b+c=180........ 2

substitute 1 in 2

a+b+180-x=180

a+b-x=0

a+b=x

15) 20+90+x=180→ x=70

x = a because their 2 sides are equal(isocelese)

a=70

70+90+d=180

d=20

a+b+c+d=180

70+20+b+c=180

b+c=90

20+42+x+y=180

x+y=118

y=118-x

y=118-70

y=48

b=y isocelese triangle

b=48

b+y+42+c=180

48+48+42+c=180

180-138=c

42=c

14)draw a parallel line Passing through the point of angle x by co interior angles property

we get,

x=180-(30+10) =140