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4. sum of triangle is 180°
by ASP A+B+C=180
50+BC=180
BC= 180-50
=130°
5..p= 4×S
26=4×S
26/4=S
4.5 cm
area of square is s×s
4.5×4.5=20.25 cm^2
by ASP A+B+C=180
50+BC=180
BC= 180-50
=130°
5..p= 4×S
26=4×S
26/4=S
4.5 cm
area of square is s×s
4.5×4.5=20.25 cm^2
Answered by
68
4] Given ,
∆ ABC Is An Isosceles Triangle .
Angle A = 50°
Let Angles B And C Be x° = 2x
[ In An Isosceles Triangle Two Side Are Equal ]
As We Know Sum Of The Angles In A Triangle = 180°
Therefore ,
Angle A + Angle B + Angle C = 180°
[ Substitute The Values ]
➡ 50 +2x = 180
➡ 2x = 180-50
➡ 2x = 130
➡ x = 130/2
➡ x = 65°
Therefore The Three Angles Are 50° , 65° , 65° .
5] Given ,
Perimeter Of The Square = 26 cm
Perimeter Of The Square = 4a
26 = 4a
a = 26/4
a = 6.5 cm
Therefore Side Of The Square = 6.5 Cm
Area Of The Square = s×s
Side Of The Square = 6.5 Cm
➡ 6.5 × 6.5
➡42.25 sq.cm
Therefore Area Of The Square = 42.25 sq.cm
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