Question

plzz answer this.........friends
.....

Answer 1

Hey user

Here is your answer :-

x^3 - 3x^2 - 4x + 12

= x^2 ( x - 3 ) - 4 ( x - 3 )

= ( x - 3 )( x^2 - 4 )

= ( x - 3 ) [ ( X )^2 - ( 2 )^2 ]

= ( x - 3 )( x - 2 )( x + 2 )

So the zeroes of the given polynomials are 3 , - 2 & 2 .

Thank you .

Answer 2

Hey guy here is ur answer :-____________________________________________________


Hope it helps you if u satisfy with this answer mark my answer as brainly