plzz................................................................ answer this guys fast
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Answered by
5
4x^2 +9y^2 - 25z^2 + 12xy
=> (2x) ^2 + (3y)^2 + 2 (2x) (3y) - (5z)^2
=> (2x +3y)^2 - (5z)^2
=> (2x +3y + 5z) (2x + 3y - 5z)
=> (2x) ^2 + (3y)^2 + 2 (2x) (3y) - (5z)^2
=> (2x +3y)^2 - (5z)^2
=> (2x +3y + 5z) (2x + 3y - 5z)
itsmebros:
thanks bro
Answered by
1
4x²+9y²-25z²+12xy
Arranging it again to make formula
We get.
(4x²+12xy+9y²)-25z²
ABOVE THE BRACKET ONE CAN BE A FORMULA OF (2x+3y)²
Then,
(2x+3y)²-5z²
Now using identity
(a²-b²) =(a+b) (a-b)
(2x+3y+5z)(2x+3y-5z)
Arranging it again to make formula
We get.
(4x²+12xy+9y²)-25z²
ABOVE THE BRACKET ONE CAN BE A FORMULA OF (2x+3y)²
Then,
(2x+3y)²-5z²
Now using identity
(a²-b²) =(a+b) (a-b)
(2x+3y+5z)(2x+3y-5z)
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