Question

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Answer 1

Answer:

150 g of CaCO₃  is required to react with Dilute HCl to give 66 g of CO₂.

Explanation:

Gram Molecular Weight of CaCO₃ = 40 + 12 + 48

                                                         = 100 g

Gram Molecular Weight of CO₂ = 12 + 32

                                                    = 44 g

Equation,

              CaCO₃ + 2HCl -------------> CaCl₂ + CO₂ + H₂O

According to the equation,

• 44 g of CO₂ is produced from 100 g of CaCO₃.
• ∴ 66 g of CO₂ will be produced from [66 × 100]÷44

                                                          = 150 g of CaCO₃       ←ANSWER

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Answer 2

Answer:

Solution is in the pic.

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