Math, asked by agutkarsh205, 10 months ago

plzz answer this it's an emergency​

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Answers

Answered by reetaranibhoi
1

Answer:

Answer :

At the end of the last year the man was saving 9930 money

Answered by shivimishra3843
8

Answer:

P = 3000

R = 10%

T = 3 year

C.I for the 1st year = 3000× 10 × 1 / 100

= 300

A = 3000 + 300

= 3300

P for the 2nd year = 3000+3300

= 6300

C.I for the 2nd year = 6300×10×1/100

= 630

A = 6300+630

= 6930

P for 3rd year = 3000 + 6930

= 9930

hope it will help you.....

mark me as brainliest......

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