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Answers
Answer:
ΔABC ≅ ΔEDC
Step-by-step explanation:
First we will find the equal angles...
∠GBA lies on the line sengment GBC. So,
the measure of ∠ABC = 180 - ∠GBA (linear pair of angles)
Similarly, as we know that ∠GBA = ∠FDE (given in question)
So, ∠EDC = 180 - ∠FDE (linear pair of angles)
We can also say that, ∠EDC = 180 - ∠GBA (because ∠FDE = ∠GBA)
∴ We can conclude that since ∠FDE = ∠GBA, So, ∠ABC = ∠EDC
Now, taking AB ║ DE, and taking line GF as a transversal, we can say that,
∠BCA = ∠DCE (vertically opposite angles)
∴ The next pair of equal angles is ∠BCA = ∠DCE
So now we have, ∠ABC = ∠EDC and ∠BCA = ∠DCE...
In the question it is also given that CB = CD
So now we have two pairss of equal angles and one pair of equal sides to verify the ASA Criterion.
∴ ∠ABC = ∠EDC, ∠BCA = ∠DCE and CB = CD
So, ΔABC ≅ ΔEDC by ASA.
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