Math, asked by sanjana12321, 10 months ago

plzz answer this plzz plzz​

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Answered by Anonymous
0

HERE'S YOUR ANSWER

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given \:  \\ one \: root =  \sqrt{3} + i \sqrt{2}   \\  \\ so \\ another =  \sqrt{3}  - i \sqrt{2}  \\  \\ sum \:  of \: roots \\  =  \sqrt{3}  + i \sqrt{2}  +  \sqrt{3}  - i \sqrt{2} \\  = 2 \sqrt{3}   \\  \\ and \: product \: of \: roots \: is \:  \\   =(  \sqrt{3}  + i \sqrt{2} )( \sqrt{3}  - i \sqrt{2} ) \\  =(  { \sqrt{3} })^{2}  -  ({i \sqrt{2} })^{2}  \\  = 3 - ( - 1) \times 2 \\  = 3 + 2 \\  = 5 \\  \\ so \: required \: equation \\  \\  {x}^{2}   -( sum) \: x + product = 0 \\  \\  =  >  {x}^{2}  - 2 \sqrt{3} x + 5 = 0

HOPE WILL HELP ✔️✔️✔️✅✅


sanjana12321: ans is wrong
Anonymous: oh
Anonymous: sry
Anonymous: but what will be the correct answer
sanjana12321: x^4-2x+25=0
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