Question

Plzz answer this ques in 10 min n answer it clearly thnx ques in pic​ if possible send pic of ans

Answer 1

$\huge\sf\blue{Given}$

✭ There is a resistor of 5Ω connect with a 10Ω and a 15Ω Resistor connected in parallel

✭ Current through the 5Ω Resistor is 1 Ampere

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$\huge\sf\gray{To \:Find}$

◈ Current through the other two resistors?

◈ Potential difference across the points AB & BC?

◈ Net resistance?

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$\huge\sf\purple{Steps}$

Question 1

As we are given the current through the 5Ω resistor we shall find the voltage,so for that we shall use the Ohm's law, that is,

$\underline{\boxed{\sf V = IR}}$

Substituting the given values for the 5Ω resistor

➝ $\sf V=IR$

➝ $\sf V=1 \times 5$

➝ $\sf\green{V=5 \ Volt}$

So now with the help of the same ohm's law we shall find the current through the other two resistors

Current through the 10Ω Resistor

➝ $\sf V=IR$

➝ $\sf 5=I\times 10$

➝ $\sf \dfrac{5}{10} = I$

➝ $\sf \red{I=0.5 \ A}$

Current through the 15Ω Resistor

➝ $\sf V=IR$

➝ $\sf 5=I\times 15$

➝ $\sf \dfrac{5}{15} = I$

➝ $\sf\red{I= 0.33 \ A}$

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Question 2

Voltage across any point of the circuit is equal so then we have already found the voltage across the 5Ω resistor. Therefore the voltage across both AB & AC will be 5 Volt

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Question 3

Here the 10Ω and the 15Ω resistors are connected in parallel and 5Ω resistor in series, equivalent resistance of a parallel connection is given by,

$\underline{\boxed{\sf\dfrac{1}{R_{net}} = \dfrac{1}{R_1} + \dfrac{1}{R_2}....\dfrac{1}{R_n}}}$

Substituting the given values,

➳ $\sf \dfrac{1}{R_{eq}} = \dfrac{1}{10} + \dfrac{1}{15}$

➳ $\sf \dfrac{1}{R_{eq}} = \dfrac{3}{30}+\dfrac{2}{30}$

➳ $\sf \dfrac{1}{R_{eq}} = \dfrac{3+2}{30}$

➳ $\sf \dfrac{1}{R_{eq}} = \dfrac{5}{30}$

➳ $\sf \dfrac{1}{R_{eq}} = \dfrac{1}{6}$

➳ $\sf R_{eq} = 6 \Omega$

So now may consider them as a series connection,then the net resistance will be,

➳ $\sf 5\Omega + 6\Omega$

➳ $\sf \orange{11 \Omega}$

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