Question

PLZZ answer this question​

Answer 1

Answer:

fufyfuxgguuggdyfch

Explanation:

xhcjlhldhpjlduugstgjzjxlfyjz

Answer 2

Answer:

option B is the answer

Explanation:

ring ka jo electric field hota hai

E = kQx / ( x^2 + R^2 ) ^3/2

ismay dekho toh E is directly proportional to x hai and x decrease hoga toh electrostatic Force bhi decrease hoga (x is the distance from the centre of ring on the axis of ring) ... Ab x decrease honay say mg dominate karega on the particle so particle apnay initial position ko chor kar niche ki taraf chalajayega yani ki ring k paas chalajayega.

2ndly hum jante hai ki at x = R/√2 par ring ka jo electric field hota hai woh maximum hota hai or we can say that the electrostatic Force applied by the ring at R/√2 is maximum....toh agar H> R/√2 par particle ko shift karte ho then ring ka electric field at H>R/√2 decrease hojayega becoz we all know infinity tak jate jate electric field ka magnitude decrease hote jata hai and tum electric field due to ring k graph say bhi dekh sakte ho

.....toh ab at H>R/√2 par electric field force decrease hogaya but mg act kar raha hai and mg particle ko wapas say initial point may ladega ....so option B is correct