Question

plzz answer this question​

Answer 1

Answer:

In the (i) no image: The area is 20 $cm^{2}$

In the (ii) no image: The area is 424 $cm^{2}$

Step-by-step explanation:

In the (i) no image:

  ABCDE = ABC + ACED

ACED is a Square.   [AE = ED = 4, ∠AED = 90°]

∴ Area of ACED = $4^{2}$

                            = 16 $cm^{2}$

ABC is a Triangle.

The Hight of ΔABC = 6 - 4 = 2 $cm$

The Base of ΔABC = 4 $cm$ [ED = AC]

∴ Area of ΔABC = $\frac{1}{2}$ × Base × Hight

                            = $\frac{1}{2}$ × 4 × 2

                            = 4 $cm^{2}$

∴ The full area of ABCDE = ABC + ACED

                                          = 4 + 16

                                          = 20 $cm^{2}$(ans)

In the (ii) no image:

  ABCDEF = ABCF + CDEF

ABCF is a Square.  [ AB = BC = CF = FA]

∴ Area of ABCF = $18^{2}$

                           = 324 $cm^{2}$

CDEF is a Trapezium. [CF║ED]

The Summation of The Parallel Sides = CF + ED

                                                              = 18 + 7 [AB = BC = CF = FA]

                                                              = 25 $cm$

The Distance Between The Parallel Sides = 8 $cm$

∴ Area of CDEF = $\frac{1}{2}$ × Distance Between Parallel Sides × Sum of Parallel Sides

                           =  $\frac{1}{2}$ × 8 × 25

                           = 100 $cm^{2}$

∴ The full area of ABCDEF = ABCF + CDEF

                                              = 324 + 100

                                              = 424 $cm^{2}$  (ans)

Hope you understand the process...

By- Md. Mominur Islam Mhaim.