Question

plzz answer this question

Answer 1

Ans.

Let, the numbers are x and y.

Then,
$\frac{x + y}{2} = 15 \\ or \: x + y = 30$
............(i)
and
$\sqrt{xy} = 9 \\ or \: xy = 81$
...........(ii)

From (i) and (ii), we eliminate x.

Then, from (ii), we write -
y(30-y) = 81
$or \: 30y - {y}^{2} = 81 \\ or \: {y}^{2} - 30y + 81 = 0 \\ or \: (y - 27)(y - 3) = 0 \\ \\ so \: y = 27 \: or \: y = 3$

From (i), we get -
x = 3 or x = 27.

So the numbers are 27 and 3; 3 and 27.

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