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HEYA!
☆GIVEN - BM = DN
Angles BMR = DNR = 90°
☆ TO PROVE - AC bisect BD i.e. DR = BR
☆ PROOF -
In Triangles DNR and BMR ,
BM = DN (given)
Angles BMR = DNR = 90° (given)
Angles DRN = BRM (vertically opposite angles)
Therefore, Triangles DNR and BMR are congruent (AAS congruency)
So DR = BR ( by CPCT )
Hence AC bisects BD .
Hope this helps!
☆GIVEN - BM = DN
Angles BMR = DNR = 90°
☆ TO PROVE - AC bisect BD i.e. DR = BR
☆ PROOF -
In Triangles DNR and BMR ,
BM = DN (given)
Angles BMR = DNR = 90° (given)
Angles DRN = BRM (vertically opposite angles)
Therefore, Triangles DNR and BMR are congruent (AAS congruency)
So DR = BR ( by CPCT )
Hence AC bisects BD .
Hope this helps!
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