Question

plzz...answer this question...

Answer 1

Answer:

Step-by-step explanation:

General term or nth term of A.P

The general term or nth term of A.P is given by an = a + (n – 1)d,

where a is the first term, d is the common difference and n is the number of term.

----------------------------------------------------------------------------------------------------

Solution:

Given:first term(a)= 121 

common difference (d)= 117- 121 = -4

∵ n th term of an AP

an = a + (n – 1)d

⇒121+(n-1) ×(-4)

⇒121-4n+4

⇒12+4-4n

⇒125 -4n

an= 125 -4n

For first negative term , an <0

⇒ 125-4n<0

⇒125<4n

⇒4n>125

⇒n>125/4

⇒n> 31 1/4

least integral value of n= 32

Hence, 32nd term of the given AP is the first negative term. 

Answer 2

hi,

Solution:

Given:first term(a)= 121 

common difference (d)= 117- 121 = -4

∵ n th term of an AP

an = a + (n – 1)d

121+(n-1) ×(-4)

121-4n+4

12+4-4n

125 -4n

an= 125 -4n

For first negative term , an <0

125-4n<0

125<4n

4n>125

n>125/4

n>311/4

least integral value of n= 32

*therefore 32nd term of the given AP is the negative term*

hope helps you!!