Plzz answer this question 9th cbse Chapter motion Physics
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1 . BC
2. 60m
3. 900m/s
bro it's not clear that what is on y axis like it is in x axis sec
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Answer:
1) BC region of graph show retardation.
2) distance travelled in first 10sec = area of rectangle formed( 0 to 10 and A to B)
= length × breadth
= 60 × 10
= 600
therefore, distance travelled = 600 m
3) total distance travelled = area of graph
= area of rectangle (A to B) + area of triangle (10 to BC)
=( l × b) + 1/2 base ×height
= (60 × 10) + 1/2×10×60
= 600+300
= 900 m
time = 20sec
speed = distance/time
= 900/20
= 45 m/s
therefore, speed = 45 m/s
Explanation:
hope it helps you
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