Physics, asked by fl969737, 9 months ago

Plzz answer this question 9th cbse Chapter motion Physics

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Answers

Answered by aryanbartwal
0

Answer:

1 . BC

2. 60m

3. 900m/s

bro it's not clear that what is on y axis like it is in x axis sec

Answered by niishaa
1

Answer:

1) BC region of graph show retardation.

2) distance travelled in first 10sec = area of rectangle formed( 0 to 10 and A to B)

= length × breadth

= 60 × 10

= 600

therefore, distance travelled = 600 m

3) total distance travelled = area of graph

= area of rectangle (A to B) + area of triangle (10 to BC)

=( l × b) + 1/2 base ×height

= (60 × 10) + 1/2×10×60

= 600+300

= 900 m

time = 20sec

speed = distance/time

= 900/20

= 45 m/s

therefore, speed = 45 m/s

Explanation:

hope it helps you

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