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Area of //gm = b × h
45 = RS × PM
45 = 9 × PM {RS = PQ (opposite side of a //gm are equal.)}
Therefore, PM = 5 cm Ans ___________
In ∆ PSM and ∆ RNS
/_M =/_N (90°)
/_NRS = /_PSR (alt. angle)
Therefore, ∆ PSM ~ ∆RNS ( AA similarity )
Now, SN/PM =SR/PS
6/5 =9/PS
Therefore, PS = 7.5 cm
Hence, PS = QR =7.5 cm Ans______
Hope this helps you!☺️
45 = RS × PM
45 = 9 × PM {RS = PQ (opposite side of a //gm are equal.)}
Therefore, PM = 5 cm Ans ___________
In ∆ PSM and ∆ RNS
/_M =/_N (90°)
/_NRS = /_PSR (alt. angle)
Therefore, ∆ PSM ~ ∆RNS ( AA similarity )
Now, SN/PM =SR/PS
6/5 =9/PS
Therefore, PS = 7.5 cm
Hence, PS = QR =7.5 cm Ans______
Hope this helps you!☺️
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