Question

plzz answer this question fastly​

Answer 1

Δ$S_v_a_p_o_u_r=$ Δ $H_v_a_p_o_u_r$/ $T_b_p$

​$T_b_p=$ 78.5 + 273 = 351.5 K

Substituting values we get;

109.8 = Δ$H_v_a_p_o_u_r$ / 351.5

Δ$H_v_a_p_o_u_r$ = 109.8 × 351.5

Δ$H_v_a_p_o_u_r$ = 38594 J mol⁻¹

or,

38.594 kJ mol⁻

Hence, option​ (c) is correct if we take approximately.