Math, asked by sanku1525, 1 year ago

plzz answer this question in detail to get 20 points​

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Answers

Answered by sainikkumarsuman
2

Answer:

factor of 81e^4-1=(9e^2+1)

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Answered by adrija70
2

Answer:

Correct option is option b

Step-by-step explanation:

81e² - 1 = (9e²)² - 1²

= (9e² + 1) (9e² - 1)

applied formula = (a² - b²)

Hence, (9e² + 1) is a factor

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