Question

plzz answer this question it's urgent... 13 points..

Answer 1

Hello !
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Solve x - √(25-x²) = 1 
          x + 1           = √(25-x²)
 Squaring both sides 
        ( x + 1)²         = 25 - x²
          x² + 1 + 2x  =  25 -x² 
          x² + x² +2x + 1 - 25 = 0 
          2x² + 2x - 24           = 0 
dividing both sides by 2 
            x² + x   - 24  = 0 
            here 
a = 1 
b = 1 
c = -24 
D = b² - 4ac 
    = 1-4(1)(-24) 
    = 1 + 48 
    = 49 
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The Quadratic equation have two roots 
-b+√D/2a      I   -b-√d/2a
-1 + √49 /2    I  -1-√49/2
-1+7/2           I  -1-7/2
6/2                I   -8/2 
3     and   -4 
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So x = 3 or -4 
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Answer 2

Answer:

Step-by-step explanation:

Solve x - √(25-x²) = 1 

         x + 1           = √(25-x²)

 Squaring both sides 

       ( x + 1)²         = 25 - x²

         x² + 1 + 2x  =  25 -x² 

         x² + x² +2x + 1 - 25 = 0 

         2x² + 2x - 24           = 0 

dividing both sides by 2 

           x² + x   - 24  = 0 

           here 

a = 1 

b = 1 

c = -24 

D = b² - 4ac 

   = 1-4(1)(-24) 

   = 1 + 48 

   = 49 

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The Quadratic equation have two roots 

-b+√D/2a      I   -b-√d/2a

-1 + √49 /2    I  -1-√49/2

-1+7/2           I  -1-7/2

6/2                I   -8/2 

3     and   -4 

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So x = 3 or -4 

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