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Step-by-step explanation:
In ΔΔCPQ and ΔΔCAB,
∠PCQ=∠ACB∠PCQ=∠ACB [As PQ || AB, corresponding angles are equal.]
∠C=∠C∠C=∠C [Common angle]
Hence, ΔΔCPQ ~ ΔΔCAB by AA criterion for similarity
So, we have
CP/CA=CQ/CBCP/CA=CQ/CB
CP/CA=4.8/8.4=4/7CP/CA=4.8/8.4=4/7
Thus, CP/PA=4/3
( 2 )
in triangle cpq and triangle abc
angle p.c.q = angle acb ( pq is parallel to ab so the angles are corresponding angles)
angle c = angle c .......( common angle)
:. triangle pcq congruent to triangle acb .......( A.A.S congruent rule)
=> pq/ab=cq/cb
=> pq/6.3=8.4/4.8
=> pq = 3.6
( 3 ) let us make a equation
ap / pc = 4/3 = x = (ac)
so the value of x maybe -3/4 ( sending 4/3 to L.H.S)
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