Question

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Answer 1

Answer:

Step-by-step explanation:

In ΔΔCPQ and ΔΔCAB,

∠PCQ=∠ACB∠PCQ=∠ACB [As PQ || AB, corresponding angles are equal.]

∠C=∠C∠C=∠C [Common angle]

Hence, ΔΔCPQ ~ ΔΔCAB by AA criterion for similarity

So, we have

CP/CA=CQ/CBCP/CA=CQ/CB

CP/CA=4.8/8.4=4/7CP/CA=4.8/8.4=4/7

Thus, CP/PA=4/3

( 2 )

in triangle cpq and triangle abc

angle p.c.q = angle acb   (  pq is parallel to ab so  the angles are corresponding angles)

angle c = angle c .......( common angle)

:. triangle pcq congruent to triangle acb .......( A.A.S congruent rule)

=> pq/ab=cq/cb

=> pq/6.3=8.4/4.8

=> pq = 3.6

( 3 ) let us make a equation

ap / pc = 4/3 = x = (ac)

so the value of x maybe -3/4 ( sending 4/3 to L.H.S)

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