Question

plzz answer this question urgent ​

Answer 1

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Step-by-step explanation:

In ∆ABC

AC is hypothenus

thetha is at angle angle C

cosec thetha =1/sin thetha=AC/AB

Sec thetha=Hypothenus/adjustan=AC/CB

This is your answer.

Answer 2

Answer:

cosec Ф = AC/AB

sec Ф = AC/BC

Step-by-step explanation:

Hii Mate ^_^

sin Ф = AB/AC

So,

cosec Ф = 1/sinФ = 1 / (AB/AC)

              = AC/AB

By seeing figure,

cos Ф = (Adjacent Side) / (Hypotenuse)

          = BC/AC

So,

sec Ф = 1/cos Ф = 1 / (BC/AB)

          = AC/BC

HOPE IT HELPS,

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