Math, asked by Anonymous, 9 months ago

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Answered by meceka03
0

In triangle ABC we have

angle A + angle B + angle C = 180° (since sum of all angles is 180°)

angle A + 70° + 20° = 180°

angle A = 180° - 90° = 90°

In triangle AMB we have

angle ABM + angle BAM + angle AMB = 180°

70° + 20° + angle AMB = 180°

angle AMB = 180°-90° = 90°

In triangle AMC we have

angle AMC + angle ACM + angle MAC = 180°

90° + 20° + angle MAC = 180°

angle MAC = 180°- 110° = 70°

Now we know that AN is bisector of Angle A .

Angle A = 90°

angle A = angle BAN + angle NAC

so angle BAN = angle NAC = 45° ( since AN is bisecting angle A )

now

Angle BAN = angle BAM + angle MAN

45°= 20° + angle MAN

angle MAN = 45°- 20° = 25°

hence found

Answered by shilpiawasthi403
1

Answer:

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