plzz answer this question with proper steps
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X4+ax3-7x-8x+6
X4+ax3-15x+6
X(4+3a)-3(5x-2)
(X-3) (4+3a)(5x-2)
This is one method of solving!!!!
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Answer:
when (x+2) and (x+3) divide it completely , it means remainder will be zero .
putting x = -2 we get,
f(-2) = (-2)⁴+a(-2)³-7(-2)²-8(-2)+b
= 16 -8a -28+16 +b
8a-b = 4 ------------ (1)
putting x = -3 now ,
f(-3) = (-3)⁴+a(-3)³ -7(-3)²-8(-3) +b
= 81 -27a -63 +24 +b
27a-b = 42 -----------(2)
subtracting first from 2nd now eqn we get ,
(27a-8a) = 38
19a = 38
a = 2
putting in any now , we get b = 12 (Ans)
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