Physics, asked by sugarcandy1536, 9 months ago

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Answered by Atαrαh
3

Between points A and B :

Three resistors R 1 , R 2 ,R 3 of resistance 6 ohm ,3 ohm and 2 ohm respectively are arranged in Parallel combination O

Equivalent resistance for resistances arranged in Parallel combination is given by the formula

 \implies{ \frac{1}{R  \: eq } =  \frac{1}{R  1}  +  \frac{1}{R2}  +  \frac{1}{R3} }

 \implies{ \frac{1}{R  \: eq } =  \frac{1}{6}  +  \frac{1}{3}  +  \frac{1}{2} }

 \implies{ \frac{1}{R  \: eq } =  \frac{1 + 2 + 3}{6} }

 \boxed{R  \: eq  = 1 \Omega}

The equivalent resistance between points A and B is 1 ohm

Between points A and C :

Two resistors R eq and R 4 of resistances 1 ohm and 1 ohm are connected in Series

Equivalent resistance for resistances arranged in series combination is given by the formula

 \implies{ Rs \:  = R1 + R2}

 \implies{ Rs \:  = 1 + 1}

 \boxed{Rs \:  =2\Omega}

The equivalent resistance between point A and C is 2 ohm

Answered by Anonymous
2

hope this will help you

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